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vladkeeeee1
@vladkeeeee1
July 2022
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Таша11111
А) 3х-4х+5≥0
-х≥-5
х≤5
х€ (-бесконечность;5]
b) (3(2+x)+12-4x)/12<0
6+3x+12-4x<0
-x+18<0
x>18
x€ (18; +...)
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Answers & Comments
-х≥-5
х≤5
х€ (-бесконечность;5]
b) (3(2+x)+12-4x)/12<0
6+3x+12-4x<0
-x+18<0
x>18
x€ (18; +...)