1) решать уравнение)) 1) 2x^2-6x=0 2) 7+2x^2=2(x+1)(x+3) 2) решать 1) 5a+10 2) 49+7b 3) 6m-12-2n+mn. Created by samiraabbasova1. algebra-ru

1) решать уравнение)) 1) 2x^2-6x=0 2) 7+2x^2=2(x+1)(x+3) 2) решать 1) 5a+10 2) 4...

July 2022 1 5 Report

1) решать уравнение))
1) 2x^2-6x=0
2) 7+2x^2=2(x+1)(x+3)

2) решать
1) 5a+10
2) 49+7b
3) 6m-12-2n+mn

Answers & Comments

NastyaKanseva 1)2x^2-6x=0
2x(x-3)=0
2x=0. x=0
x-3=0. x=3

2)7+2x^2=(x+1)(x+3)
7+2x^2=x^2+4x+3
7+2x^2-x^2-4x-3=0
4+x^2-4x=0
4-4x+x^2=0
(2-x)^2=0
2-x=0
x=2

3)5a+10=5(a-2)
4)49+7b=7(7+b)
5)6m-12-2n+mn=6(m-2)-n(2-m)=-(6+n)(2-m)

samiraabbasova1 спасибо большое:))))))

NastyaKanseva пожалуйста

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1) (p-2)(p+3)-(p+1)(p-6) p=123 2) (y-4)^2= 3) (7x+a)^2=...

1) 2p-6 2) 4p-32a (p-2)(p+3)-(p+1)(p-6)= p=123...

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Answers & Comments

reshat uravneniya 1 72x22x1x3 2y2 7y0 1 2p 6 2 4p 32a

1) (p-2)(p+3)-(p+1)(p-6) p=123 2) (y-4)^2= 3) (7x+a)^2=...

1) 2p-6 2) 4p-32a (p-2)*(p+3)-(p+1)*(p-6)= p=123...

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1) 2p-6 2) 4p-32a (p-2)(p+3)-(p+1)(p-6)= p=123...