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samiraabbasova1
@samiraabbasova1
July 2022
1
7
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1) решать уравнение))
1) 2x^2-6x=0
2) 7+2x^2=2(x+1)(x+3)
2) решать
1) 5a+10
2) 49+7b
3) 6m-12-2n+mn
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Answers & Comments
NastyaKanseva
1)2x^2-6x=0
2x(x-3)=0
2x=0. x=0
x-3=0. x=3
2)7+2x^2=(x+1)(x+3)
7+2x^2=x^2+4x+3
7+2x^2-x^2-4x-3=0
4+x^2-4x=0
4-4x+x^2=0
(2-x)^2=0
2-x=0
x=2
3)5a+10=5(a-2)
4)49+7b=7(7+b)
5)6m-12-2n+mn=6(m-2)-n(2-m)=-(6+n)(2-m)
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samiraabbasova1
спасибо большое:))))))
NastyaKanseva
пожалуйста
NastyaKanseva
пожалуйста
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Answers & Comments
2x(x-3)=0
2x=0. x=0
x-3=0. x=3
2)7+2x^2=(x+1)(x+3)
7+2x^2=x^2+4x+3
7+2x^2-x^2-4x-3=0
4+x^2-4x=0
4-4x+x^2=0
(2-x)^2=0
2-x=0
x=2
3)5a+10=5(a-2)
4)49+7b=7(7+b)
5)6m-12-2n+mn=6(m-2)-n(2-m)=-(6+n)(2-m)