Ответ:
t=x^2;
t^2-5t+4=0
D=(-5)^2-4*4=25-16=9=3^2
t1=
t2=
x1==
x2=
x3==
x4==
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Verified answer
Ответ:
t=x^2;
t^2-5t+4=0
D=(-5)^2-4*4=25-16=9=3^2
t1=
t2=
x1=
=
x2=

x3=
=
x4=
=