Упростите выражение
а) (sint+cost)^2/1+2sin t cos t
b) 1-2sin t cos t/(cos t-si t)^2
докажите торжество
а) cos^2 t/1-sin t -sint t=1
а) (sint+cost)^2/(1+2sin t cos t)=(sin^2t+2sint cost+cos^2t)/(1+2sint cost)=(1+2sint cost)/(1+2sint cost)=1
b) (1-2sin t cos t)/(cos t-si t)^2=(1-2sint cost)/(cos^2t-2sint cost+sin^2t)=(1-2sint cost)/(1-2sint cost)=1
a) cos^2 t/1-sin t -sint t=1
((1-sin^2t)-sint(1-sint))/(1-sint)=1
(1-sin^2t-sint+sin^2t)/(1-sint)=1
(1-sint)/(1-sint)=1
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Verified answer
а) (sint+cost)^2/(1+2sin t cos t)=(sin^2t+2sint cost+cos^2t)/(1+2sint cost)=(1+2sint cost)/(1+2sint cost)=1
b) (1-2sin t cos t)/(cos t-si t)^2=(1-2sint cost)/(cos^2t-2sint cost+sin^2t)=(1-2sint cost)/(1-2sint cost)=1
a) cos^2 t/1-sin t -sint t=1
((1-sin^2t)-sint(1-sint))/(1-sint)=1
(1-sin^2t-sint+sin^2t)/(1-sint)=1
(1-sint)/(1-sint)=1