Home
О нас
Products
Services
Регистрация
Войти
Поиск
Bombilkaa
@Bombilkaa
July 2022
1
5
Report
упрости выражения (1-sin^2a)/(cos^2a), (1-cos^2a)/(1-sin^2a), (1+tg^2a)*cos^2a-sin^2a, (ctg^2a+1)*sin^2a-cos^2a
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
zarembo73
(1-sin
²
a)/(cos
²
a)=cos
²α/cosα=1;
(1-cos
²
a)/(1-sin
²
a)=sin
²α/cos²α=tg²;
(1+tg
²
a)*cos
²
a-sin
²
a=1/(cos
²α)*cos²α-sin²α=1-sin²α=cos²α;
(ctg
²
a+1)*sin
²
a-cos
²
a=1/(sin
²α)*sin²α-cos²α=1-cos²α=sin²α.
1 votes
Thanks 2
More Questions From This User
See All
Bombilkaa
March 2022 | 0 Ответы
vo vseh podrobnostyah zadachu
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "(1-sin^2a), (1+tg^2a)*cos^2a-sin^2a, (ctg^2a+1)*sin^2a-cos^2a..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
(1-cos²a)/(1-sin²a)=sin²α/cos²α=tg²;
(1+tg²a)*cos²a-sin²a=1/(cos²α)*cos²α-sin²α=1-sin²α=cos²α;
(ctg²a+1)*sin²a-cos²a=1/(sin²α)*sin²α-cos²α=1-cos²α=sin²α.