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osminog21
@osminog21
July 2022
1
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1) sinx+sin2x+sin3x=0
2)sin2x=cosx cos2x
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Monkey2015
1)sinx sin2x sin3x=0
sinx=0 sin2x=0
sin3x=0
x=pi*k, k∈Z
2x=pi*k, k∈Z
3x=pi*k, k∈Z
x=pi*k/2, k∈Z
x=pi*k/3, k∈Z
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Answers & Comments
sinx=0 sin2x=0 sin3x=0
x=pi*k, k∈Z 2x=pi*k, k∈Z 3x=pi*k, k∈Z
x=pi*k/2, k∈Z x=pi*k/3, k∈Z