K₂Cr₂O₇ + 14 HCl → 2CrCl₃ + 3Cl₂ + 2KCl + 7H₂O
Cr⁶⁺ + 3e ----> Cr³⁺ | 2
2Cl⁻ - 2e = Cl₂⁰ | 3
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
K₂Cr₂O₇ + 14 HCl → 2CrCl₃ + 3Cl₂ + 2KCl + 7H₂O
Cr⁶⁺ + 3e ----> Cr³⁺ | 2
2Cl⁻ - 2e = Cl₂⁰ | 3