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taniachaika61
@taniachaika61
March 2022
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1 вариант химия помогите, задачи
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mrvladimir2
Verified answer
1. m(p-pa) = 40 г + 160 г = 200 г
ω = 40 г/200 г ×100% = 20%
1= 200=40=160=20
2. m(р.в-ва) = 400 г×50%/100% = 200 г
m(H2O) = 400 г - 200 г = 200 г
2=400=200=200=50
3. m(р.в-ва) = 500 г - 300 г = 200 г
ω=200 г/500 г ×100% = 40%
3=500=200=300=40
2 votes
Thanks 1
taniachaika61
спасибо большое
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Answers & Comments
Verified answer
1. m(p-pa) = 40 г + 160 г = 200 гω = 40 г/200 г ×100% = 20%
1= 200=40=160=20
2. m(р.в-ва) = 400 г×50%/100% = 200 г
m(H2O) = 400 г - 200 г = 200 г
2=400=200=200=50
3. m(р.в-ва) = 500 г - 300 г = 200 г
ω=200 г/500 г ×100% = 40%
3=500=200=300=40