№1. Вычислите.а) ((10-1 2\3*1 1\2*2 1\5)*(1\4:9\8+1\3)-1 1\2):3 1\3 =б) ((1 1\4*1 1\3*1 1\5-1 1\10)*(2-7\8:3\4)+3)*3 3\4 =. Created by ikspert. matematika-ru

((10-1 2\3*1 1\2*2 1\5)*(1\4:9\8+1\3)-1 1\2):3 1\3 = ----------------------------------------------------------------------------------------((1 1\4*1 1\3*1 1\5-1 1\10)*(2-7\8:3\4)+3)*3 3\4 =

№1. Вычислите.а) ((10-1 2\3*1 1\2*2 1\5)*(1\4:9\8+1\3)-1 1\2):3 1\3 =б) ((1 1\4*...

ikspert @ikspert

July 2022 1 13 Report

№1. Вычислите.
а) ((10-1 2\3*1 1\2*2 1\5)*(1\4:9\8+1\3)-1 1\2):3 1\3 =
б) ((1 1\4*1 1\3*1 1\5-1 1\10)*(2-7\8:3\4)+3)*3 3\4 =

Answers & Comments

AnLen84 ((10-1 2\3*1 1\2*2 1\5)*(1\4:9\8+1\3)-1 1\2):3 1\3 = $\frac{3}{10}=0,3$

$1\frac{2}{3} *1 \frac{1}{2}*2 \frac{1}{5}= \frac{5*3*11}{3*2*5}= \frac{11}{2}=5 \frac{1}{2}$

$10-5 \frac{1}{2}=10- \frac{11}{2}= \frac{20-11}{2}= \frac{9}{2}=4 \frac{1}{2}$

$\frac{1}{4}: \frac{9}{8}= \frac{1*8}{4*9}= \frac{2}{9}$

$\frac{2}{9}+ \frac{1}{3}= \frac{2+3}{9}= \frac{5}{9}$

$4\frac{1}{2}* \frac{5}{9}= \frac{9}{2}* \frac{5}{9}= \frac{5}{2}= 2\frac{1}{2}$

$2 \frac{1}{2}-1 \frac{1}{2}= \frac{5-3}{2}= \frac{2}{2}=1$

$1: 3\frac{1}{3}=1: \frac{10}{3}=1* \frac{3}{10}=0,3$

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((1 1\4*1 1\3*1 1\5-1 1\10)*(2-7\8:3\4)+3)*3 3\4 = $14 \frac{1}{16}$

$1 \frac{1}{4}* 1 \frac{1}{3}*1 \frac{1}{5}= \frac{5*4*6}{4*3*5}=2$

$2-1 \frac{1}{10}=1 \frac{10}{10}-1 \frac{1}{10}= \frac{9}{10}=0,9$

$\frac{7}{8}: \frac{3}{4}= \frac{7*4}{8*3}= \frac{7}{6}=1 \frac{1}{6}$

$2-1 \frac{1}{6}=1 \frac{6}{6}-1 \frac{1}{6}= \frac{5}{6}$

$\frac{9}{10}* \frac{5}{6}= \frac{3}{4}$

$3+ \frac{3}{4}=3 \frac{3}{4}$

$3 \frac{3}{4}*3 \frac{3}{4}= \frac{15*15}{16}= \frac{225}{16}=14 \frac{1}{16}$

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