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Furmanova99
@Furmanova99
July 2022
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1) x² - x - 12 = 0
2) (x+1)(x²-3x) = 0
3) (3x - 5) (x+2) = x²-5x - 2
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nafanya2014
Verified answer
1) x² - x - 12 = 0 D=(-1)²-4·(-12)=49
x₁=(1-7)/2=-3 или х₂=(1+7)/2=4
Ответ. х=-3; х=4
2) (x+1)(x²-3x) = 0
(х+1)х(х-3)=0
х+1=0 или х=0 или х-3=0
х=-1 х=0 х=3
Ответ.х= -1; х=0; х=3
3) (3x - 5) (x+2) = x²-5x - 2
3х²-5х+6х-10=х²-5х-2
2х²+6х-8=0
х²+3х-4=0
D=9+16=25
x₁=(-3-5)/2=-4 или х₂=(-3+5)/2=1
Ответ. х=-4; х=1
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Answers & Comments
Verified answer
1) x² - x - 12 = 0 D=(-1)²-4·(-12)=49x₁=(1-7)/2=-3 или х₂=(1+7)/2=4
Ответ. х=-3; х=4
2) (x+1)(x²-3x) = 0
(х+1)х(х-3)=0
х+1=0 или х=0 или х-3=0
х=-1 х=0 х=3
Ответ.х= -1; х=0; х=3
3) (3x - 5) (x+2) = x²-5x - 2
3х²-5х+6х-10=х²-5х-2
2х²+6х-8=0
х²+3х-4=0
D=9+16=25
x₁=(-3-5)/2=-4 или х₂=(-3+5)/2=1
Ответ. х=-4; х=1