1) x² - x - 12 = 0 2) (x+1)(x²-3x) = 0 3) (3x - 5) (x+2) = x²-5x - 2. Created by Furmanova99. algebra-ru

1) x² - x - 12 = 0 2) (x+1)(x²-3x) = 0 3) (3x - 5) (x+2) = x²-5x

Furmanova99 @Furmanova99

July 2022 1 4 Report

1) x² - x - 12 = 0
2) (x+1)(x²-3x) = 0
3) (3x - 5) (x+2) = x²-5x - 2

Answers & Comments

nafanya2014

Verified answer

1) x² - x - 12 = 0 D=(-1)²-4·(-12)=49
x₁=(1-7)/2=-3    или    х₂=(1+7)/2=4
Ответ. х=-3; х=4
2) (x+1)(x²-3x) = 0
   (х+1)х(х-3)=0
х+1=0    или х=0 или х-3=0
х=-1 х=0 х=3
Ответ.х= -1; х=0; х=3
3) (3x - 5) (x+2) = x²-5x - 2
   3х²-5х+6х-10=х²-5х-2
    2х²+6х-8=0
   х²+3х-4=0
D=9+16=25
x₁=(-3-5)/2=-4    или    х₂=(-3+5)/2=1
Ответ. х=-4; х=1

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