1) x x^2+y^2 x ____ +_______ - ____

July 2022 1 13 Report

1) x x^2+y^2 x
____ +_______ - _____
x-y y^2-x^2 x-y

2) 2x-3+2(x-1)=4(x-1)-7

3)2x+3-6(x-1)=4(1-x)+5

4) найдите значение выражения (2a^-3 b^-5 ) ^-2 если а=2;b= 1
___
2

5)найдите значение а если известно что прямая ax+2y=6 проходит через точку A(4;1)

Answers & Comments

Artem112

Verified answer

$\frac{x}{x-y} + \frac{x^2+y^2}{y^2-x^2} - \frac{x}{x-y} =\frac{x^2+y^2}{y^2-x^2}$
$2x-3+2(x-1)=4(x-1)-7
\\
2x-3+2x-2=4x-4-7
\\
4x-5 \neq 4x-11$
$2x+3-6(x-1)=4(1-x)+5
\\\
2x+3-6x+6=4-4x+5
\\\
9-4x=9-4x
\\\
x\in R$
$(2a^{-3 } b^{-5} ) ^{-2}= \frac{a^6b^{10}}{4} = \frac{2^6\cdot0.5^{10}}{4} = \frac{0.5^4}{4} = \frac{1}{2^6} =0.015625$
$4a+2\cdot1=6
\\\
4a+2=6
\\\
4a=4
\\\
a=1$

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