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colac
@colac
November 2021
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№ 1. Запишіть у вигляді многочлена стандартного вигляду:
1) 3(4а – 1) – 2(12а + 3) + 2а; 2) х2 – 2х – 8 – (2х2 + х – 7);
3) 2х7(3х2 – x + 1); 4) (3a – 2b)(2a – 5b); 5) 2х3у2(-1,6х4у3 + 3,4х2у);
6) (a – 4b)(2a2 + ab – 2b2); 7) (2х2 – 4х + 3
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gyulnazaryans
12а-3-24а-6+2а=14а-3
4 votes
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