х²-х-4=0
a=1 b=(-1) c=(-4)
D=b^2-4ac=(-1)^2-4*1*(-4)=√17
x1=(1+√17)/(2)
x2=(1-√17)/(2)
Ответ:
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х²-х-4=0
a=1 b=(-1) c=(-4)
D=b^2-4ac=(-1)^2-4*1*(-4)=√17
x1=(1+√17)/(2)
x2=(1-√17)/(2)
Ответ:
x1=(1+√17)/(2)
x2=(1-√17)/(2)