Verified answer

m(ZnCl2) = 10 kg = 10 000 g

m(Zn) - ?
n(ZnCl2) = 10 000 g / 136 g / mol = 73.529 mol = 73.53 mol

Zn + 2HCl = ZnCl2 + H2

за УХР: n(Zn) = n(ZnCl2) = 73.53 mol ;

m(Zn) = 73.53 mol * 65 g / mol = 4779.45 g = 4779.5 g = 4780 g

Ответ: 4780 g || 4.78 kg .