Verified answer

Объяснение:

[tex]log_{\sqrt[4]{7}} 169=log_{7^\frac{1}{4} }13^2=4*2*log_713=8*log_713=a.\\8*log_713=a\ |:8\\log_713=\frac{a}{8}.\ \ \ \ \ \Rightarrow\\[/tex]

[tex]log_{7\sqrt{7}} \frac{49}{13}=log_{7^\frac{3}{2}}\frac{7^2}{13} =\frac{2}{3}* log_7\frac{7^2}{13} =\frac{2}{3}*(log_77^2-log_713)=\frac{2}{3} *(2-log_713)=[/tex]

[tex]=\frac{2}{3} *(2-\frac{a}{8})=\frac{2}{3}*\frac{2*8-a}{8} =\frac{2*(16-a)}{3*8}=\frac{16-a}{12}.[/tex]