Ответ:
1)x=5
2)x>5
Объяснение:
1)log[1/5](5*x)=-2
log[1/5](5*x) = -2*log[1/5](1/5)
log[1/5](5*x)=log[1/5](25)
5*x=25
x=5
2)log[1/5](5*x)<-2
log[1/5](5*x) < -2*log[1/5](1/5)
log[1/5](5*x)<log[1/5](25)
5*x>25
x>5
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Verified answer
Ответ:
1)x=5
2)x>5
Объяснение:
1)log[1/5](5*x)=-2
log[1/5](5*x) = -2*log[1/5](1/5)
log[1/5](5*x)=log[1/5](25)
5*x=25
x=5
2)log[1/5](5*x)<-2
log[1/5](5*x) < -2*log[1/5](1/5)
log[1/5](5*x)<log[1/5](25)
5*x>25
x>5