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pasha8874
@pasha8874
July 2022
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10 баллов Помогите пожалуйста а и б решите пршу
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Ruslan007007008009
а)
б)
0 votes
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pasha8874
можно подробнее особенно сразу в начале
pasha8874
в 1 и 2 в начале
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Answers & Comments
а)![(\frac{m}{mn - n^{2}} - \frac{1}{m-n} ):\frac{n}{n-m} = \frac{m-n}{mn-n^{2}} * \frac{n-m}{n} = \frac{(m-n)(n-m)}{n^{2}(m-n)} = \frac{n-m}{n^{2}} (\frac{m}{mn - n^{2}} - \frac{1}{m-n} ):\frac{n}{n-m} = \frac{m-n}{mn-n^{2}} * \frac{n-m}{n} = \frac{(m-n)(n-m)}{n^{2}(m-n)} = \frac{n-m}{n^{2}}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bm%7D%7Bmn%20-%20n%5E%7B2%7D%7D%20-%20%5Cfrac%7B1%7D%7Bm-n%7D%20%29%3A%5Cfrac%7Bn%7D%7Bn-m%7D%20%3D%20%5Cfrac%7Bm-n%7D%7Bmn-n%5E%7B2%7D%7D%20%2A%20%5Cfrac%7Bn-m%7D%7Bn%7D%20%3D%20%5Cfrac%7B%28m-n%29%28n-m%29%7D%7Bn%5E%7B2%7D%28m-n%29%7D%20%3D%20%5Cfrac%7Bn-m%7D%7Bn%5E%7B2%7D%7D)
б)![(\frac{1}{m-n} - \frac{n}{m^{2}-mn} )*\frac{n-m}{m} = \frac{m-n}{m^{2}-mn} *\frac{n-m}{m} = \frac{(m-n)(n-m)}{m^{2}(m-n)} = \frac{n-m}{m^{2}} (\frac{1}{m-n} - \frac{n}{m^{2}-mn} )*\frac{n-m}{m} = \frac{m-n}{m^{2}-mn} *\frac{n-m}{m} = \frac{(m-n)(n-m)}{m^{2}(m-n)} = \frac{n-m}{m^{2}}](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7Bm-n%7D%20-%20%5Cfrac%7Bn%7D%7Bm%5E%7B2%7D-mn%7D%20%29%2A%5Cfrac%7Bn-m%7D%7Bm%7D%20%3D%20%5Cfrac%7Bm-n%7D%7Bm%5E%7B2%7D-mn%7D%20%2A%5Cfrac%7Bn-m%7D%7Bm%7D%20%3D%20%5Cfrac%7B%28m-n%29%28n-m%29%7D%7Bm%5E%7B2%7D%28m-n%29%7D%20%3D%20%5Cfrac%7Bn-m%7D%7Bm%5E%7B2%7D%7D)