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ozhiginvania
@ozhiginvania
November 2021
0
5
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10 баллов.
Помогите, просто времени нету. Условные знаки - (3a^2) т.е. 3a во 2 степени.
Докажите тождество:
2) (4-3a^2)-a^2+(7+2a^2)-(-2a^2+11)=0
3) (x^3+4^2)-(x+6)+(1+x-x^3)=4x^2-5
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