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Issu1503d001
@Issu1503d001
July 2022
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найдите sinx,если cosx=3корень11/10 и 270*<X<360*
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JekaMikcyl
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Sinx^2+cosx^2=1
cosx=√(1-9*11/100)=+√(0.01)=+0.1 т. к. cosx>0 при 0<x<90
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Sinx^2+cosx^2=1cosx=√(1-9*11/100)=+√(0.01)=+0.1 т. к. cosx>0 при 0<x<90