[tex]1)\\\\\frac{a-3}{\sqrt a - \sqrt 3}=\frac{(\sqrt {a})^2-(\sqrt 3)^3}{\sqrt a - \sqrt 3}=\frac{(\sqrt a - \sqrt 3)(\sqrt a +\sqrt 3)}{\sqrt a - \sqrt 3}=\sqrt a + \sqrt 3}[/tex]
[tex]3)\\\\\frac{a-b}{\sqrt a - \sqrt b}=\frac{(\sqrt a)^2-(\sqrt b)^2}{\sqrt a - \sqrt b}=\frac{(\sqrt a - \sqrt b)(\sqrt a +\sqrt b)}{\sqrt a - \sqrt b}=\sqrt a + \sqrt b}[/tex]
2 votes Thanks 1
timonpobeditel
А как просмотреть ответ? у меня половина ответов в английских словах
Answers & Comments
Ответ:
[tex]1)\ \sqrt a + \sqrt 3}[/tex]
[tex]2)\ \sqrt {2x}-\sqrt 5[/tex]
[tex]3)\ \sqrt a + \sqrt b}[/tex]
Объяснение:
[tex]1)\\\\\frac{a-3}{\sqrt a - \sqrt 3}=\frac{(\sqrt {a})^2-(\sqrt 3)^3}{\sqrt a - \sqrt 3}=\frac{(\sqrt a - \sqrt 3)(\sqrt a +\sqrt 3)}{\sqrt a - \sqrt 3}=\sqrt a + \sqrt 3}[/tex]
[tex]2)\\\\\frac{2x-5}{\sqrt {2x}+\sqrt 5}=\frac{(\sqrt{2a})^2-(\sqrt 5)^2}{\sqrt {2x}+\sqrt 5}=\frac{(\sqrt {2x}+\sqrt 5)(\sqrt {2x}-\sqrt 5)}{\sqrt {2x}+\sqrt 5}=\sqrt {2x}-\sqrt 5[/tex]
[tex]3)\\\\\frac{a-b}{\sqrt a - \sqrt b}=\frac{(\sqrt a)^2-(\sqrt b)^2}{\sqrt a - \sqrt b}=\frac{(\sqrt a - \sqrt b)(\sqrt a +\sqrt b)}{\sqrt a - \sqrt b}=\sqrt a + \sqrt b}[/tex]