Ответ:
[tex]1)3 {a}^{3} ( {a}^{2} - 3a + 1) = 3 {a}^{5} - 9 {a}^{4} + 3 {a}^{3} \\ 2)(3x - 5)(x - 8) = 3 {x}^{2} - 24x - 5x + 40 = 3 {x}^{2} - 29x + 40 \\ 3) {(4x - 1)}^{2} = 16 {x}^{2} - 8x + 1\\ 4)(4a - 5b)(4a + 5b)16 {a}^{2} - 25 {b}^{2} [/tex]
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Ответ:
[tex]1)3 {a}^{3} ( {a}^{2} - 3a + 1) = 3 {a}^{5} - 9 {a}^{4} + 3 {a}^{3} \\ 2)(3x - 5)(x - 8) = 3 {x}^{2} - 24x - 5x + 40 = 3 {x}^{2} - 29x + 40 \\ 3) {(4x - 1)}^{2} = 16 {x}^{2} - 8x + 1\\ 4)(4a - 5b)(4a + 5b)16 {a}^{2} - 25 {b}^{2} [/tex]