Verified answer

Ответ: ( 1 ; 3 )

Объяснение:

[tex]\left \{ \begin{array}{l}5y -6x =9 \\\\ 4x+3y=13 \end{array}\right. \Leftrightarrow \left \{ \begin{array}{l}5y =6x+9 \\\\ 3y=13-4x \end{array}\right. \Leftrightarrow \left \{ \begin{array}{l}y = \cfrac{6x+9}{5} \\\\ y=\cfrac{13-4x}{3} \end{array}\right. \\\\\\ \displaystyle \cfrac{6x+9}{5} =\cfrac{13-4x}{3} \\\\ 3(6x+9) = 5(13-4x) \\\\ 18x+27 = 65 -20 x \\\\ 18x+20x= 65-27 \\\\ 38 x = 38 \\\\ x= 1 \\\\ y = \cfrac{6x+9}{5} = 3[/tex]