Воспользуемся т. Виета
[tex]\displaystyle x^2+px+q=0\\\\\left \{ {{x_1+x_2=-p} \atop {x_1*x_2=q}} \right.[/tex]
тогда
[tex]\displaystyle x^2+px-30=0\\\\\left \{ {{x_1+x_2=-p} \atop {x_1*x_2=-30}} \right. \\\\x_1=-10\\\\-10*x_2=-30\\\\x_2=3\\\\-10+3=-7\\\\-7=-p\\\\p=7\\\\x^2+7x-30=0[/tex]
Ответ:
x²+px-30=0
x1×x2=-30
-10×x2=30
x2=3
x1+x2=p
-10+3=-7
x2+7x-30=0
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Verified answer
Воспользуемся т. Виета
[tex]\displaystyle x^2+px+q=0\\\\\left \{ {{x_1+x_2=-p} \atop {x_1*x_2=q}} \right.[/tex]
тогда
[tex]\displaystyle x^2+px-30=0\\\\\left \{ {{x_1+x_2=-p} \atop {x_1*x_2=-30}} \right. \\\\x_1=-10\\\\-10*x_2=-30\\\\x_2=3\\\\-10+3=-7\\\\-7=-p\\\\p=7\\\\x^2+7x-30=0[/tex]
Ответ:
x²+px-30=0
x1×x2=-30
-10×x2=30
x2=3
x1+x2=p
-10+3=-7
x2+7x-30=0