Ответ:
1)m²-7m+6=0
D=b²-4ac=(-7)²-4*1*6=49-24=[tex]\sqrt{25}[/tex]=5
m₁=[tex]\frac{-(-7)+5}{2*1} =\frac{12}{2}=6[/tex]
m₂=[tex]\frac{-(-7)-5}{2*1}=\frac{2}{2}=1[/tex]
2)x²-6x=0
x(x-6)=0
x=0 или x-6=0
x=6
3)Д=1+168=169
у=( -1+13): 12=1
у=-14/12=-7/6
4)5x^2-125=0
5x^2=125
x^2=25
x=(-5)(5)
5)(x+4)^2=3*x^2-8 ⇒[tex]\left \{ {{x=6}\atop{x=-2}} \right.[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Ответ:
1)m²-7m+6=0
D=b²-4ac=(-7)²-4*1*6=49-24=[tex]\sqrt{25}[/tex]=5
m₁=[tex]\frac{-(-7)+5}{2*1} =\frac{12}{2}=6[/tex]
m₂=[tex]\frac{-(-7)-5}{2*1}=\frac{2}{2}=1[/tex]
2)x²-6x=0
x(x-6)=0
x=0 или x-6=0
x=6
3)Д=1+168=169
у=( -1+13): 12=1
у=-14/12=-7/6
4)5x^2-125=0
5x^2=125
x^2=25
x=(-5)(5)
5)(x+4)^2=3*x^2-8 ⇒[tex]\left \{ {{x=6}\atop{x=-2}} \right.[/tex]