Ответ:
P = 32 sm
S = 32[tex]\sqrt{3}[/tex] sm'2
Объяснение:
MOL - priamougolniy
KLM=60, togda MLO=30, a uzhe s etogo MO=0.5ML
znachit ML=8 sm
P = 8 * 4 = 32 sm
OL'2 po Pifagoru = ML'2 - OM'2 =64 - 16 =48 sm'2
OL = 4 [tex]\sqrt{3}[/tex] sm
Togda NL=2OL=8 [tex]\sqrt{3}[/tex] sm
MK=2MO=8 sm
S = 0.5 * 8 * 8[tex]\sqrt{3}[/tex] = 32[tex]\sqrt{3}[/tex] sm'2
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Ответ:
P = 32 sm
S = 32[tex]\sqrt{3}[/tex] sm'2
Объяснение:
MOL - priamougolniy
KLM=60, togda MLO=30, a uzhe s etogo MO=0.5ML
znachit ML=8 sm
P = 8 * 4 = 32 sm
OL'2 po Pifagoru = ML'2 - OM'2 =64 - 16 =48 sm'2
OL = 4 [tex]\sqrt{3}[/tex] sm
Togda NL=2OL=8 [tex]\sqrt{3}[/tex] sm
MK=2MO=8 sm
S = 0.5 * 8 * 8[tex]\sqrt{3}[/tex] = 32[tex]\sqrt{3}[/tex] sm'2