Ответ:

[tex]\frac{1}{16} p^{2} +2py +16y^{2}[/tex]

Объяснение:

[tex](\frac{1}{4} p+4y)^{2} =[/tex]

[tex]= (\frac{1}{4} p+4y)*(\frac{1}{4} p+4y) =[/tex]

[tex]=\frac{1}{4} p*(\frac{1}{4} p+4y)+4y *(\frac{1}{4} p+4y) =[/tex]

[tex]=(\frac{1}{4} p*\frac{1}{4}p+\frac{1}{4} p*4y)+(4y *\frac{1}{4} p +4y*4y) =[/tex]

[tex]=(\frac{1}{16} p^{2} +py)+(py +16y^{2} ) =[/tex]

[tex]=\frac{1}{16} p^{2} +py+py +16y^{2} =[/tex]

[tex]=\frac{1}{16} p^{2} +2py +16y^{2}[/tex]