Ответ:
Пошаговое объяснение:
2) [tex]-\frac{2}{3}\sqrt{54}=\sqrt{(-\frac{2}{3})^{2}*54}=\sqrt{\frac{4}{9}*54}=\sqrt{4*6}=\sqrt{24}[/tex] в)
1) [tex]\sqrt{450}=\sqrt{25*2*9}=15\sqrt{2}[/tex] а)
3)[tex]\sqrt{a^{2}*3}=a\sqrt{3}[/tex] в)
[tex]\frac{2}{9}\sqrt{\frac{27}{28}}=\sqrt{(\frac{2}{9})^{2}\frac{27}{28}}=\sqrt{\frac{4}{81}*\frac{27}{28}}=\sqrt{\frac{1}{21}}[/tex] в)
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Ответ:
Пошаговое объяснение:
2) [tex]-\frac{2}{3}\sqrt{54}=\sqrt{(-\frac{2}{3})^{2}*54}=\sqrt{\frac{4}{9}*54}=\sqrt{4*6}=\sqrt{24}[/tex] в)
1) [tex]\sqrt{450}=\sqrt{25*2*9}=15\sqrt{2}[/tex] а)
3)[tex]\sqrt{a^{2}*3}=a\sqrt{3}[/tex] в)
[tex]\frac{2}{9}\sqrt{\frac{27}{28}}=\sqrt{(\frac{2}{9})^{2}\frac{27}{28}}=\sqrt{\frac{4}{81}*\frac{27}{28}}=\sqrt{\frac{1}{21}}[/tex] в)