Verified answer

[tex]\displaystyle\bf\\\left \{ {{x\geq -5} \atop {x < 7}} \right.[/tex]

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-------------[ - 5]----------------(7)-----------

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[tex]\displaystyle\bf\\Otvet \ : \ x\in\Big[-5 \ ; \ 7\Big)\\\\\\2)\\\\\left \{ {{\dfrac{x}{4}+\dfrac{x}{2} \geq -1} \atop {2(x-4)-5x < 8-x}} \right. \\\\\\\left \{ {{\dfrac{x}{4}\cdot 4+\dfrac{x}{2} \cdot 4 \geq -1\cdot 4} \atop {2x-8-5x < 8-x}} \right. \\\\\\\left \{ {{x+2x\geq -4} \atop {-7x-8 < 8-x}} \right. \\\\\\\left \{ {{3x\geq -4} \atop {-7x+x < 8+8}} \right. \\\\\\\left \{ {{x\geq -1\dfrac{1}{3} } \atop {-6x < 16}} \right.[/tex]

[tex]\displaystyle\bf\\\left \{ {{x\geq -1\dfrac{1}{3} } \atop {x > -2\dfrac{2}{3} }} \right. \ \ \ \Rightarrow \ \ \ x\geq -1\frac{1}{3} \\\\\\Otvet \ : \ x\in\Big[-1\frac{1}{3} \ ; \ +\infty\Big)[/tex]