[tex]\displaystyle\bf\\b_{1} =2\\\\b_{4} =-54\\\\b_{2} =? \ \ ; \ \ b_{3} =?\\\\\\b_{4} =b_{1}\cdot q^{3} \\\\\\q^{3}=b_{4}:b_{1}=-54:2=-27\\\\\\q=\sqrt[3]{-27} =\sqrt[3]{(-3)^{3} } =-3\\\\\\b_{2}=b_{1} \cdot q=2\cdot (-3)=-6\\\\\\b_{3}=b_{2} \cdot q=-6\cdot (-3)=18\\\\\\Otvet \ : \ 2 \ \ ; \ \ -6 \ \ ; \ \ 18 \ \ ; \ \ -54[/tex]
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
[tex]\displaystyle\bf\\b_{1} =2\\\\b_{4} =-54\\\\b_{2} =? \ \ ; \ \ b_{3} =?\\\\\\b_{4} =b_{1}\cdot q^{3} \\\\\\q^{3}=b_{4}:b_{1}=-54:2=-27\\\\\\q=\sqrt[3]{-27} =\sqrt[3]{(-3)^{3} } =-3\\\\\\b_{2}=b_{1} \cdot q=2\cdot (-3)=-6\\\\\\b_{3}=b_{2} \cdot q=-6\cdot (-3)=18\\\\\\Otvet \ : \ 2 \ \ ; \ \ -6 \ \ ; \ \ 18 \ \ ; \ \ -54[/tex]