Ответ:

1)У ∆LKM (∠K = 90°; NL = 24; NK = 25)

sinL = 24/25 (Ця рівність правильна)

2 завдання

1

.BC = 7, A = 37, B = 90-37 = 53, AB = BC/sin A = 7/sin 37

AC = AB*cos A = 7/sin 37*cos 37 = 7*ctg 37

2.

AC = 8, BC = 5, AB = √(AC^2 + BC^2) = √(64+25) = √89

cos A = sin B = AC/AB = 8/√89,

A = arccos(8/√89), B = arcsin(8/√89)

а якщо треба вот ще задачі

AB = 8, AC = 5, BC = √(AB^2 - AC^2) = √(64-25) = √39

cos A = sin B = AC/AB = 5/8,

A = arccos(5/8), B = arcsin(5/8)

BC = 7, A = 37, B = 90-37 = 53, AB = BC/sin A = 7/sin 37

AC = AB*cos A = 7/sin 37*cos 37 = 7*ctg 37