решение уравнений на фото

[tex]\displaystyle\bf\\1)\\\\x^{2} +5x-14=0\\\\Teorema \ Vieta \ : \ \\\\x_{1} + x_{2} =-5\\\\x_{1} \cdot x_{2} =-14\\\\x_{1} =-7 \ \ \ ; \ \ \ x_{2} =2\\\\2)\\\\x^{2} -14x+40=0\\\\Teorema \ Vieta \ : \ \\\\x_{1} + x_{2} =14\\\\x_{1} \cdot x_{2} =40\\\\x_{1} =4 \ \ \ ; \ \ \ x_{2} =10\\\\3)\\\\x^{2} -6x-27=0\\\\Teorema \ Vieta \ : \ \\\\x_{1} + x_{2} =6\\\\x_{1} \cdot x_{2} =-27\\\\x_{1} =-3 \ \ \ ; \ \ \ x_{2} =9[/tex]

[tex]\displaystyle\bf\\4)\\\\x^{2} -9x+20=0\\\\Teorema \ Vieta \ : \ \\\\x_{1} + x_{2} =9\\\\x_{1} \cdot x_{2} =20\\\\x_{1} =4 \ \ \ ; \ \ \ x_{2} =5[/tex]