[tex]\displaystyle\bf\\1)\\\\\frac{3x}{y}\cdot\frac{y^{2} }{x^{2} } =\frac{3\cdot x\cdot y \cdot y}{y\cdot x\cdot x}=\frac{3y}{x} \\\\2)\\\\\frac{15x^{2} y}{14a} \cdot \frac{7a}{5xy^{2} } =\frac{5xy\cdot 3x\cdot 7a}{7a\cdot 2 \cdot 5xy\cdot y} =\frac{3x}{2y} \\\\3)\\\\\frac{x+2}{17} \cdot\frac{34x}{x^{2}+4x+4 }=\frac{(x+2)\cdot 17\cdot 2x}{17\cdot(x+2)^{2} } =\frac{2x}{x+2} \\\\4)[/tex]
[tex]\displaystyle\bf\\(x-5)\cdot\frac{18x}{9x^{2}-225 }=\frac{(x-5)\cdot 18x}{9\cdot(x^{2} -25)} =\frac{(x-5)\cdot 9\cdot 2x}{9\cdot(x -5)\cdot (x+5)} = \frac{2x}{x+5}[/tex]
Решение на прикреплённой фотографии
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
[tex]\displaystyle\bf\\1)\\\\\frac{3x}{y}\cdot\frac{y^{2} }{x^{2} } =\frac{3\cdot x\cdot y \cdot y}{y\cdot x\cdot x}=\frac{3y}{x} \\\\2)\\\\\frac{15x^{2} y}{14a} \cdot \frac{7a}{5xy^{2} } =\frac{5xy\cdot 3x\cdot 7a}{7a\cdot 2 \cdot 5xy\cdot y} =\frac{3x}{2y} \\\\3)\\\\\frac{x+2}{17} \cdot\frac{34x}{x^{2}+4x+4 }=\frac{(x+2)\cdot 17\cdot 2x}{17\cdot(x+2)^{2} } =\frac{2x}{x+2} \\\\4)[/tex]
[tex]\displaystyle\bf\\(x-5)\cdot\frac{18x}{9x^{2}-225 }=\frac{(x-5)\cdot 18x}{9\cdot(x^{2} -25)} =\frac{(x-5)\cdot 9\cdot 2x}{9\cdot(x -5)\cdot (x+5)} = \frac{2x}{x+5}[/tex]
Решение на прикреплённой фотографии