Verified answer

[tex]x = 0.02 = \frac{1}{50} \\ y = \frac{1}{3} \\ ( \frac{1}{4}x - \frac{2}{3} y) {}^{3} - \frac{3\%}{100\%} y = \\ = ( \frac{1}{4} \times \frac{1}{50} - \frac{2}{3} \times \frac{1}{3} ) {}^{3} - \frac{3}{100 \times 3} = \\ = ( \frac{1}{200} - \frac{2}{9} ) {}^{3} - \frac{1}{100} = \\ = ( \frac{9 - 400}{1800} ) {}^{3} - \frac{1}{100} = \\ = (- \frac{391}{1800} ) {}^{3} - \frac{1}{100} = \\ = - \frac{59776471}{5832000000} - \frac{1}{100} = \\ = \frac{ - 59776471 - 58320000}{5832000000} = \\ = - \frac{5890320000}{5832000000} = \\ = - \frac{101}{100} = - 1.01[/tex]