[tex]\displaystyle\bf\\\left \{ {{0.5(x - 4y) - 16 = x + 3y} \atop {4(x - 3y) + 39 = \frac{1}{3}(6x + y) }} \right. \\ \displaystyle\bf\\\left \{ {{0.5x - 2y - x - 3y = 16} \atop {4x - 12y - 2x - \frac{y}{3} = - 39 }} \right. \\ \displaystyle\bf\\\left \{ {{ - 0.5x - 5y =1 6 \: \: | \times 10} \atop {2x - 12 \frac{1}{3} y = - 39 \: \: | \times 3}} \right. \\ \displaystyle\bf\\\left \{ {{ - 5x - 50y = 160 \: \: | \times 6 } \atop {6x - 37y = - 117 \: \: | \times 5 }} \right. \\ \displaystyle\bf\\ + \left \{ {{ - 30x - 300y = 960} \atop {30x - 185y = - 585 }} \right. \\ \\ - 300y - 185y = 960 - 585 \\ - 485y = 375 \\ y = - \frac{375}{485} \\ y = - \frac{75}{97} \\ \\ 6x - 37 \times ( - \frac{75}{97} ) = - 117 \\ 6x + \frac{2775}{97} = - 117 \\ 6x + 28 \frac{59}{97} = - 117 \\ 6x = - 117 - 28 \frac{59}{97} \\ 6x = - 145 \frac{59}{97} \\ x = - 145 \frac{59}{97} \div 6 \\ x = - \frac{14124}{97 \times 6} \\ x = - \frac{2354}{97} \\ x = - 24 \frac{26}{97} [/tex]

Ответ: ( - 24 26/97 ; - 75/97 )