[tex]\displaystyle\bf\\\left \{ {{ \frac{2(x - y)}{3} + 1.6 = \frac{8x}{15} - \frac{3y - 10}{5} \: \: | \times 15 } \atop { \frac{3x + 4}{4} + \frac{y}{8} = \frac{5x}{6} - \frac{y - 17}{12} \: \: | \times 24 }} \right. \\ \displaystyle\bf\\\left \{ {{10(x - y) + 24 = 8x - 3(3y - 10)} \atop {6(3x + 4) + 3y = 20x - 2(y - 17) }} \right. \\ \displaystyle\bf\\\left \{ {{10x - 10y + 24 = 8x - 9y + 30} \atop {18x + 24 + 3y = 20x - 2y + 34 }} \right. \\ \displaystyle\bf\\\left \{ {{10x - 8x - 10y + 9y = 30 - 24} \atop {18x - 20x + 3y + 2y = 34 - 24 }} \right. \\ \displaystyle\bf\\ + \left \{ {{2x - y = 6} \atop { - 2x + 5y = 10 }} \right. \\ \\ 5y - y = 10 + 6 \\ 4y = 16 \\ y = 16 \div 4 \\ y = 4 \\ \\ 2x - 4 = 6 \\ 2x = 6 + 4 \\ 2x = 10 \\ x = 10 \div 2 \\ x = 5[/tex]

Ответ: ( 5 ; 4 )