[tex]y = \sqrt{ \frac{1}{x + 1} } = \frac{1}{ \sqrt{x + 1} } \\ x + 1 > 0 \\ x > - 1[/tex]
Ответ: 2)
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[tex]y = \sqrt{ \frac{1}{x + 1} } = \frac{1}{ \sqrt{x + 1} } \\ x + 1 > 0 \\ x > - 1[/tex]
Ответ: 2)