[tex]f(x) = x + 3 \\ F(x) = \frac{ {x}^{1 + 1} }{1 + 1} + 3x + C = \frac{ 1 }{2} {x}^{2} + 3x + C[/tex]
Ответ: Г)
[tex]f(x) = \sqrt[3]{x} = {x}^{ \frac{1}{3} } \\ F(x) = \frac{x {}^{ \frac{1}{3} + 1} }{ \frac{1}{3} + 1 } + C = \frac{x {}^{ \frac{1}{3} + \frac{3}{3} } }{ \frac{1}{3} + \frac{3}{3} } + C = \frac{ {x}^{ \frac{4}{3} } }{ \frac{4}{3} } + C = \\ = \frac{3}{4} \sqrt[3]{ {x}^{4} } + C[/tex]
Ответ: А)
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Answers & Comments
1
[tex]f(x) = x + 3 \\ F(x) = \frac{ {x}^{1 + 1} }{1 + 1} + 3x + C = \frac{ 1 }{2} {x}^{2} + 3x + C[/tex]
Ответ: Г)
2
[tex]f(x) = \sqrt[3]{x} = {x}^{ \frac{1}{3} } \\ F(x) = \frac{x {}^{ \frac{1}{3} + 1} }{ \frac{1}{3} + 1 } + C = \frac{x {}^{ \frac{1}{3} + \frac{3}{3} } }{ \frac{1}{3} + \frac{3}{3} } + C = \frac{ {x}^{ \frac{4}{3} } }{ \frac{4}{3} } + C = \\ = \frac{3}{4} \sqrt[3]{ {x}^{4} } + C[/tex]
Ответ: А)