Ответ:
Объяснение:
1. В2. Б
3. Г
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[tex]\frac{2m}{m-3} + \frac{m}{m+3} + \frac{2m^{2}}{9-m^{2}} = \frac{2m(m+3)}{(m-3)(m+3)} + \frac{m(m-3)}{(m+3)(m-3)} + \frac{2m^{2}}{(m+3)(m-3)} = \frac{2m(m+3) + m(m-3) + 2m^{2}}{(m+3)(m-3)} = \frac{5m^{2} + 3m}{(m+3)(m-3)}[/tex]
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Answers & Comments
Ответ:
Объяснение:
1. В
2. Б
3. Г
4.
5.
6.
7.
[tex]\frac{2m}{m-3} + \frac{m}{m+3} + \frac{2m^{2}}{9-m^{2}} = \frac{2m(m+3)}{(m-3)(m+3)} + \frac{m(m-3)}{(m+3)(m-3)} + \frac{2m^{2}}{(m+3)(m-3)} = \frac{2m(m+3) + m(m-3) + 2m^{2}}{(m+3)(m-3)} = \frac{5m^{2} + 3m}{(m+3)(m-3)}[/tex]
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