Verified answer

Ответ:

[tex](0;0)\\\\(-0,5;-3)[/tex]

Объяснение:

[tex]\left \{ {{y=-12x^2} \atop {y=6x}} \right. \\\\\left \{ {{y=-12x^2} \atop {-12x^2=6x}} \right. \\\\-12x^2=6x\\\\-12x^2-6x=0\ \ \ |:(-6)\\\\2x^2+x=0\\\\x(2x+1)=0\\\\x=0\ \ \ \ \ \ \ \ 2x+1=0\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2x=-1\ \ \ \ |:2\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=-0,5[/tex]

[tex]\left \{ {{x=0} \atop {y=6x}} \right. \\\\\left \{ {{x=0} \atop {y=6\cdot 0}} \right. \\\\\left \{ {{x=0} \atop {y=0}} \right. \\[/tex]                         [tex]\left \{ {{x=-0,5} \atop {y=6x}} \right. \\\\\left \{ {{x=-0,5} \atop {y=6\cdot (-0,5)} \right. \\\\\left \{ {{x=-0,5} \atop {y=-3}} \right. \\[/tex]

Объяснение:

у= -12х²

у=6х

-12х²=6х

-12х²-6х=0

-6х(2х+1)=0

-6х=0 2х+1=0

х=0 2х= -1

х= -1/2

у=6•0=0

у=6•(-1/2)= -3

Точки пересечения графиков :

(0;0) ; ( -1/2; -3)