Ответ:

пусть m(CxHy) = 100r

m mathcal C =85,7^ * 100r1100\%= 85.7Gamma

m(H)= 100 - 85 ,7=14.3r

nC = mM =85,7 backslash12=7,14

n(H) =14,3 backslash1=14,3

C: H = 7.14 * 0.14 * 0.3 = 1.2

CH2, C2H4

M(C2H4)=12^ * 2+1^ * 4 = 28

M(CxHy) =D(H2)*M(H2)=21^ * 2=42r \Morb Ответ С3Н6 пропен