Verified answer

1)

а) 3√2 и √20

3√2=√18

√18 < √20 => 3√2 < √20

б) √14 и 2√3

2√3=√12

√12 < √14 => √14  > 2√3

в) 7√3 и 3√7

7√3=√147

3√7=√63

√147 > √63 => 7√3 > 3√7

2)

а) 2/3√63 и 1/2√104

4/9*63 и 1/4*104

28>26 => 2/3√63>1/2√104

в) 0,7√10/7 и 0.9√2/3

(7/10)^2*10/7 и (9/10)^2*2/3

49/100*10/7 и 81/100*2/3

7/10 и 27/50

350 > 270 => 0,7√10/7 > 0,9√2/3

Verified answer

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