Відповідь:
w = Ar(X) * a * 100%
Mr(CaCO3) = 40 + 12 + 16*3 = 100
w(Ca) = 40 * 1 * 100% = 40%
w(C) = 12 * 1 * 100% = 12%
w(О) = 16 * 3 * 100% = 48 %
Mr(HCl) = 1+35,5 =36,5г/моль
w(H) = 1/36,5 ×100% = 2,7%
w(Cl) = 100% - 2,7% = 97,3%w(ca)=40 дробь 104 ×100℅ =38
w(cI)=70 дробь 104 ×100℅= 63M(CO2)=12+32=44
w(O)=32/44*100=73%
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Відповідь:
w = Ar(X) * a * 100%
Mr(CaCO3) = 40 + 12 + 16*3 = 100
w(Ca) = 40 * 1 * 100% = 40%
w(C) = 12 * 1 * 100% = 12%
w(О) = 16 * 3 * 100% = 48 %
Mr(HCl) = 1+35,5 =36,5г/моль
w(H) = 1/36,5 ×100% = 2,7%
w(Cl) = 100% - 2,7% = 97,3%
w(ca)=40 дробь 104 ×100℅ =38
w(cI)=70 дробь 104 ×100℅= 63
M(CO2)=12+32=44
w(O)=32/44*100=73%