Ответ:
Мr(Сr₂O₃) = 52 * 2 + 16 * 3 = 152
Mr(Cr) = 52 * 2 = 104
w%(Cr) = 104 : 152 * 100 % = 68,42
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Ответ:
Мr(Сr₂O₃) = 52 * 2 + 16 * 3 = 152
Mr(Cr) = 52 * 2 = 104
w%(Cr) = 104 : 152 * 100 % = 68,42