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begimaikk7
@begimaikk7
August 2022
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ПОМОГИТЕ. геометрической прогрессии n-найдите формулу члена а) 4/1, 6/1, 9/1, ...; б) 4, -1, 4/1
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liana200005
А) аn=a(n-1)*q
6=4*q
q=1,5
an=a1*q(n-1)=а1*1,5(n-1)
б) аn=a(n-1)*q
4=-1*q
q=-4
an=a1*q(n-1)=a1*(-4)n-1))
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Answers & Comments
6=4*q
q=1,5
an=a1*q(n-1)=а1*1,5(n-1)
б) аn=a(n-1)*q
4=-1*q
q=-4
an=a1*q(n-1)=a1*(-4)n-1))