Ответ:
Вычисляем значение выражения, учитывая порядок действий .
[tex]\bf \dfrac{((7-6,35):6,5+9,9)\cdot \dfrac{1}{12,8}}{(1,2:36+1\dfrac{1}{5}:0,25-1\dfrac{5}{6})\cdot 1\dfrac{1}{4}}:0,125=1\dfrac{4}{21}[/tex]
[tex]\bf 1)\ \ ((7-6,35):6,5+9,9)\cdot \dfrac{1}{12,8}=(0,65:6,5+9,9)\cdot \dfrac{10}{128}=\\\\=(0,1+9,9)\cdot \dfrac{5}{64}=10\cdot \dfrac{5}{64}=\dfrac{50}{64}=\dfrac{25}{32}[/tex]
[tex]\displaystyle \bf 2)\ \ \Big(1,2:36+1\dfrac{1}{5}:0,25-1\dfrac{5}{6}\Big)\cdot 1\dfrac{1}{4}=\Big(\dfrac{12}{360}+\frac{6}{4}:\frac{1}{4}-\frac{11}{6}\Big)\cdot \frac{5}{4}=\\\\\\=\Big(\dfrac{1}{30}+\frac{6}{4}\cdot \frac{4}{1}-\frac{11}{6}\Big)\cdot \frac{5}{4}=\Big(\dfrac{1}{30}+6-\frac{11}{6}\Big)\cdot \frac{5}{4}=\frac{1+180-55}{30}\cdot \frac{5}{4}=\\\\\\=\frac{126}{6}\cdot \frac{1}{4}=\frac{21}{1}\cdot \frac{1}{4}=\frac{21}{4}[/tex]
[tex]\displaystyle \bf 3)\ \ \frac{\dfrac{25}{32}}{\dfrac{21}{4}}:0,125=\frac{25\cdot 4}{32\cdot 21}:\frac{1}{8}=\frac{25\cdot 4\cdot 8}{32\cdot 21}=\frac{25}{21}=1\frac{4}{21}[/tex]
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Answers & Comments
Ответ:
Вычисляем значение выражения, учитывая порядок действий .
[tex]\bf \dfrac{((7-6,35):6,5+9,9)\cdot \dfrac{1}{12,8}}{(1,2:36+1\dfrac{1}{5}:0,25-1\dfrac{5}{6})\cdot 1\dfrac{1}{4}}:0,125=1\dfrac{4}{21}[/tex]
[tex]\bf 1)\ \ ((7-6,35):6,5+9,9)\cdot \dfrac{1}{12,8}=(0,65:6,5+9,9)\cdot \dfrac{10}{128}=\\\\=(0,1+9,9)\cdot \dfrac{5}{64}=10\cdot \dfrac{5}{64}=\dfrac{50}{64}=\dfrac{25}{32}[/tex]
[tex]\displaystyle \bf 2)\ \ \Big(1,2:36+1\dfrac{1}{5}:0,25-1\dfrac{5}{6}\Big)\cdot 1\dfrac{1}{4}=\Big(\dfrac{12}{360}+\frac{6}{4}:\frac{1}{4}-\frac{11}{6}\Big)\cdot \frac{5}{4}=\\\\\\=\Big(\dfrac{1}{30}+\frac{6}{4}\cdot \frac{4}{1}-\frac{11}{6}\Big)\cdot \frac{5}{4}=\Big(\dfrac{1}{30}+6-\frac{11}{6}\Big)\cdot \frac{5}{4}=\frac{1+180-55}{30}\cdot \frac{5}{4}=\\\\\\=\frac{126}{6}\cdot \frac{1}{4}=\frac{21}{1}\cdot \frac{1}{4}=\frac{21}{4}[/tex]
[tex]\displaystyle \bf 3)\ \ \frac{\dfrac{25}{32}}{\dfrac{21}{4}}:0,125=\frac{25\cdot 4}{32\cdot 21}:\frac{1}{8}=\frac{25\cdot 4\cdot 8}{32\cdot 21}=\frac{25}{21}=1\frac{4}{21}[/tex]