Объяснение:
4.
tg∠B=AC/AB
AB=AC/tg∠B=6/tgβ
5.
cos∠B=BC/AB
AB=BC/cos∠B=2/cosβ
6.
sin∠C=AB/AC
AB=AC•sin∠C=8•sinγ
Ответ:
4) ΔАВС , АС=6 см . ∠В=β
[tex]\bf tg\beta =\dfrac{AC}{AB}\ \ \ \Rightarrow \ \ \ AB=\dfrac{AC}{tg\beta }=\dfrac{6}{tg\beta }=6\cdot ctg\beta[/tex]
5) ΔАВС , ВС=2 см , ∠В=β .
[tex]\bf cos\beta =\dfrac{BC}{AB}\ \ \ \Rightarrow \ \ \ AB=\dfrac{BC}{cos\beta }=\dfrac{2}{cos\beta }[/tex]
6) ΔABC , АC=8 cм , [tex]\angle C=\gamma[/tex] .
[tex]\bf sin\gamma =\dfrac{AB}{AC}\ \ \ \Rightarrow \ \ \ AB=AC\cdot sin\gamma=8\cdot sin\gamma[/tex]
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Verified answer
Объяснение:
4.
tg∠B=AC/AB
AB=AC/tg∠B=6/tgβ
5.
cos∠B=BC/AB
AB=BC/cos∠B=2/cosβ
6.
sin∠C=AB/AC
AB=AC•sin∠C=8•sinγ
Ответ:
4) ΔАВС , АС=6 см . ∠В=β
[tex]\bf tg\beta =\dfrac{AC}{AB}\ \ \ \Rightarrow \ \ \ AB=\dfrac{AC}{tg\beta }=\dfrac{6}{tg\beta }=6\cdot ctg\beta[/tex]
5) ΔАВС , ВС=2 см , ∠В=β .
[tex]\bf cos\beta =\dfrac{BC}{AB}\ \ \ \Rightarrow \ \ \ AB=\dfrac{BC}{cos\beta }=\dfrac{2}{cos\beta }[/tex]
6) ΔABC , АC=8 cм , [tex]\angle C=\gamma[/tex] .
[tex]\bf sin\gamma =\dfrac{AB}{AC}\ \ \ \Rightarrow \ \ \ AB=AC\cdot sin\gamma=8\cdot sin\gamma[/tex]