Ответ:
1+tg²α=1/cos²α⇒1+2²=1/cos²α⇒5=1/cos²α⇒cos²α=1/5, 10*cos²α-1=10*1/5-1=2-1=1
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Ответ:
1+tg²α=1/cos²α⇒1+2²=1/cos²α⇒5=1/cos²α⇒cos²α=1/5, 10*cos²α-1=10*1/5-1=2-1=1