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Nastuha67
@Nastuha67
August 2022
1
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10х2 + 3х = 1
3х2 - 1 = 2х
(х-2)(х+2)-2х(х-3)=6-х
(х+1)2 = 1 - ( 7 +х)х
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alexooooon
10x^2 + 3x - 1 = 0;
D = b^2 - 4ac;
D = 3^2 - 4 * 10 * (-1);
D = 9 - -40 = 49;
D > 0, два корня!
x1,2 = (-b ± √D)/2a;
x1:x = (-3 + 7)/2*10;
x = 4/20; |:4
x = 1/5;
x2:x = (-3 - 7)/2*10;
x = -(10/20); |:10
x = -(1/2);
Ответ: 1/5; -(1/2).
3x^2 - 2x - 1 = 0;
D = b^2 - 4ac;
D = -2^2 - 4 * 3 * (-1);
D = 4 - -12 = 16;
D > 0, два корня!
x1,2 = (-b ± √D)/2a;
x1:x = (2 + 4)/2*3;
x = 6/6; |:6
x = 1
x2:x = (2 - 4)/2*3;
x = -(2/6); |:2
x = -(1/3);
Ответ: 1; -(1/3).
-1x^2 + 7x - 10 = 0;
D = b^2 - 4ac;
D = 7^2 - 4 * (-1) * (-10);
D = 49 - 40 = 9;
D > 0, два корня!
x1,2 = (-b ± √D)/2a;
x1:x = (-7 + 3)/2*(-1);
x = -(4/2); |:-2
x = 2;
x2:x = (-7 - 3)/2*(-1);
x = -(10/2); |:-2
x = 5;
Ответ: 2; 5.
В последнем, похоже что нужно было -х(7+х)
2x^2+9x=0
x(2x+9)=0
[x = 0 [x = 0
[2x = -9 [x = -4(1/2)
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Answers & Comments
D = b^2 - 4ac;
D = 3^2 - 4 * 10 * (-1);
D = 9 - -40 = 49;
D > 0, два корня!
x1,2 = (-b ± √D)/2a;
x1:x = (-3 + 7)/2*10;
x = 4/20; |:4
x = 1/5;
x2:x = (-3 - 7)/2*10;
x = -(10/20); |:10
x = -(1/2);
Ответ: 1/5; -(1/2).
3x^2 - 2x - 1 = 0;
D = b^2 - 4ac;
D = -2^2 - 4 * 3 * (-1);
D = 4 - -12 = 16;
D > 0, два корня!
x1,2 = (-b ± √D)/2a;
x1:x = (2 + 4)/2*3;
x = 6/6; |:6
x = 1
x2:x = (2 - 4)/2*3;
x = -(2/6); |:2
x = -(1/3);
Ответ: 1; -(1/3).
-1x^2 + 7x - 10 = 0;
D = b^2 - 4ac;
D = 7^2 - 4 * (-1) * (-10);
D = 49 - 40 = 9;
D > 0, два корня!
x1,2 = (-b ± √D)/2a;
x1:x = (-7 + 3)/2*(-1);
x = -(4/2); |:-2
x = 2;
x2:x = (-7 - 3)/2*(-1);
x = -(10/2); |:-2
x = 5;
Ответ: 2; 5.
В последнем, похоже что нужно было -х(7+х)
2x^2+9x=0
x(2x+9)=0
[x = 0 [x = 0
[2x = -9 [x = -4(1/2)