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steep6
@steep6
July 2022
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10)Помогите пожалуйста с данным примером :
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mikael2
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Z=√(x/x-1) → 3z-2.5=3/z 3z²-2.5z-3=0 стандартно найдем корни
x1= 3/2 x2=-2/3 z≥0 x2 не подходит
√(x/x-1)=3/2 x/(x-1)=9/4=2.25 x=2.25x-2.25 1.25x=2.25 x=1.8
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добрейший1
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Answers & Comments
Verified answer
Z=√(x/x-1) → 3z-2.5=3/z 3z²-2.5z-3=0 стандартно найдем корниx1= 3/2 x2=-2/3 z≥0 x2 не подходит
√(x/x-1)=3/2 x/(x-1)=9/4=2.25 x=2.25x-2.25 1.25x=2.25 x=1.8