[tex]\displaystyle (x+3\frac{4}{11})-5\frac{7}{11}=1\frac{6}{11}\\ \\(x+\frac{37}{11})-\frac{62}{11}=\frac{17}{11}\\ \\x+\frac{37}{11}-\frac{62}{11}=\frac{17}{11}\\ \\x-\frac{25}{11}=\frac{17}{11}\\ \\x=\frac{17}{11}+\frac{25}{11}\\ \\x=\frac{42}{11}=3\frac{9}{11}[/tex]